Identify X in the following reaction. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of benzene with excess chlorine in the presence of anhydrous $AlCl_3$ (a Lewis acid) in the dark and at cold conditions leads to the

Vedclass · Accepted Answer

Hexachlorobenzene

Vedclass · Answer

(B) The reaction of benzene with excess chlorine in the presence of anhydrous $AlCl_3$ (a Lewis acid) in the dark and at cold conditions leads to the electrophilic aromatic substitution of all six hydrogen atoms of the benzene ring by chlorine atoms. This process is known as exhaustive chlorination. The reaction is as follows: $C_6H_6 + 6Cl_2 \xrightarrow{	ext{Anhydrous } AlCl_3, 	ext{dark, cold}} C_6Cl_6 + 6HCl$ Here,$C_6Cl_6$ is hexachlorobenzene. Therefore,the correct option is $B$.

Identify $X$ in the following reaction.

Similar Questions

Write down the products of ozonolysis of $1, 2-$dimethylbenzene ($o-$xylene). How does the result support the Kekul\text{é} structure for benzene?

The function of anhydrous $AlCl_3$ in the Friedel-Crafts reaction is to

Thiophene and benzene are separated by

$ClCH_2-CH_2Cl$ $\xrightarrow[(ii) NaNH_2]{(i) Alc. KOH}$ $A$ $\xrightarrow{\text{Red hot Fe tube}}$ $B$
Identify product $B$ in the above reaction sequence.

What is the total number of benzene derivatives with the molecular formula $C_6H_3Cl_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module