Identify (Z) in the following reaction:CH_3CO | vedclass

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Question

(A) $LiAlH_4$ is a strong reducing agent that reduces carboxylic acids to primary alcohols.$CH_3COOH \xrightarrow{LiAlH_4} CH_3CH_2OH$ (Ethanol,$X$).H

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Aldol

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(A) $LiAlH_4$ is a strong reducing agent that reduces carboxylic acids to primary alcohols.$CH_3COOH \xrightarrow{LiAlH_4} CH_3CH_2OH$ (Ethanol,$X$).Heating primary alcohols with $Cu$ at $573 \ K$ causes dehydrogenation to form aldehydes.$CH_3CH_2OH \xrightarrow{573 \ K, \ Cu} CH_3CHO$ (Ethanal,$Y$).Ethanal contains $\alpha$-hydrogens and undergoes an aldol condensation reaction in the presence of dilute $NaOH$ to form a $\beta$-hydroxyaldehyde,commonly known as aldol.$CH_3CHO \xrightarrow{dil.NaOH} CH_3-CH(OH)-CH_2-CHO$ (Aldol,$Z$).

Identify $(Z)$ in the following reaction:
$CH_3COOH$ $\xrightarrow{LiAlH_4} (X)$ $\xrightarrow{573 \ K, \ Cu} (Y)$ $\xrightarrow{dil.NaOH} (Z)$

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Identify $(Z)$ in the following reaction:$CH_3COOH$ $\xrightarrow{LiAlH_4} (X)$ $\xrightarrow{573 \ K, \ Cu} (Y)$ $\xrightarrow{dil.NaOH} (Z)$