Identify A and B in the following reactions: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The $-NO_2$ group is a deactivating and meta-directing group. Therefore,electrophilic aromatic substitution of nitrobenzene with $Cl_2$ in th

Vedclass · Accepted Answer

$A = m	ext{-chloronitrobenzene}, B = 	ext{azobenzene}$

Vedclass · Answer

(A) $1$. The $-NO_2$ group is a deactivating and meta-directing group. Therefore,electrophilic aromatic substitution of nitrobenzene with $Cl_2$ in the presence of $Fe$ (Lewis acid) yields $m	ext{-chloronitrobenzene}$ as the major product $(A)$.$2$. The reduction of nitrobenzene with $LiAlH_4$ is a complex process. While $LiAlH_4$ is a strong reducing agent,under specific conditions,it can reduce nitrobenzene to azobenzene $(C_6H_5-N=N-C_6H_5)$ $(B)$.

Identify $A$ and $B$ in the following reactions:

Similar Questions

In the circuit shown in the figure,$R = \sqrt{\frac{L}{C}}$. Switch $S$ is closed at time $t = 0$. The current through the inductor $L$ and the capacitor $C$ would be equal after a time $t$ equal to:

Which of the following halides is most acidic?

$A$ neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is

The simplest formula of a compound containing $50\%$ of element $X$ (atomic mass $10$) and $50\%$ of element $Y$ (atomic mass $20$) is

$\cos \alpha \sin (\beta-\gamma)+\cos \beta \sin (\gamma-\alpha)+\cos \gamma \sin (\alpha-\beta)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module