Identify $A, B$ and $C$ in the following reaction:
$\text{Toluene} + A + B$ $\xrightarrow{273-283 \ K} C$ $\xrightarrow{H_3O^{\oplus}} \text{Benzaldehyde}$
$\text{Toluene} + A + B$ $\xrightarrow{273-283 \ K} C$ $\xrightarrow{H_3O^{\oplus}} \text{Benzaldehyde}$
- A$A = CrO_3, B = (CH_3CO)_2O, C = C_6H_5CH(OCOCH_3)_2$
- B$A = CrO_2Cl_2, B = CH_3COCl, C = C_6H_5CH(OH)COCH_3$
- C$A = V_2O_3, B = (CH_3CO)_2O, C = C_6H_5CH_2OCOCH_3$
- D$A = AlCl_3, B = CH_3COOH, C = C_6H_5C(OCOCH_3)_3$
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View SolutionIdentify the name of the reaction: $C_6H_5CH_3 + CrO_2Cl_2 \xrightarrow{CS_2} C_6H_5CH(OCrOHCl_2)_2 \xrightarrow{H_3O^+} C_6H_5CHO$.
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View SolutionMatch the following:
| List-$I$ | List-$II$ |
| :--- | :--- |
| $(A)$ Acid chloride to aldehyde | $(I)$ $DIBAL-H$ |
| $(B)$ Benzene to benzaldehyde | $(II)$ $CO, HCl, \text{anhyd. } AlCl_3$ |
| $(C)$ Acetylene to aldehyde | $(III)$ $HgSO_4, H_2SO_4$ |
| $(D)$ Ester to aldehyde | $(IV)$ $H_2, Pd-BaSO_4$ |
| List-$I$ | List-$II$ |
| :--- | :--- |
| $(A)$ Acid chloride to aldehyde | $(I)$ $DIBAL-H$ |
| $(B)$ Benzene to benzaldehyde | $(II)$ $CO, HCl, \text{anhyd. } AlCl_3$ |
| $(C)$ Acetylene to aldehyde | $(III)$ $HgSO_4, H_2SO_4$ |
| $(D)$ Ester to aldehyde | $(IV)$ $H_2, Pd-BaSO_4$ |
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