Identify B in the following reaction:H_4SiO_4 | vedclass

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(D) Orthosilicic acid $(H_4SiO_4)$, on heating at $1000^{\circ}C$, loses two water molecules to form silica $(SiO_2)$ as product $A$.$H_4SiO_4 \xright

Vedclass · Accepted Answer

carborundum

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(D) Orthosilicic acid $(H_4SiO_4)$, on heating at $1000^{\circ}C$, loses two water molecules to form silica $(SiO_2)$ as product $A$.$H_4SiO_4 \xrightarrow[{-2H_2O}]{1000^{\circ}C} SiO_2 (A)$Silica $(SiO_2)$ on reduction with carbon at high temperature gives carborundum $(SiC)$ as product $B$ and carbon monoxide $(CO)$.$SiO_2 + 3C \xrightarrow{\Delta} SiC (B) + 2CO$Therefore, $B$ is carborundum.

Identify $B$ in the following reaction:
$H_4SiO_4$ $\xrightarrow[{-H_2O}]{1000^{\circ}C} A$ $\xrightarrow[\Delta]{Carbon} B + CO$

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Identify $B$ in the following reaction:$H_4SiO_4$ $\xrightarrow[{-H_2O}]{1000^{\circ}C} A$ $\xrightarrow[\Delta]{Carbon} B + CO$