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(C) To determine the shapes of the molecules, we use the $VSEPR$ theory:$1$. $H_2O$: The central oxygen atom has $2$ bond pairs and $2$ lone pairs, re

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$H_2O, \,\, SCl_2$

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(C) To determine the shapes of the molecules, we use the $VSEPR$ theory:$1$. $H_2O$: The central oxygen atom has $2$ bond pairs and $2$ lone pairs, resulting in a bent ($V$-shaped) geometry.$2$. $SCl_2$: The central sulfur atom has $2$ bond pairs and $2$ lone pairs, resulting in a bent ($V$-shaped) geometry.Both $H_2O$ and $SCl_2$ have a bent shape.$3$. $NH_3$ is trigonal pyramidal, while $SO_2$ is bent.$4$. $XeF_4$ is square planar, while $SF_4$ is see-saw.$5$. $PCl_5$ is trigonal bipyramidal, while $BrF_5$ is square pyramidal.Therefore, the correct pair is $H_2O$ and $SCl_2$.

Identify a pair of molecules having similar shapes of both members.

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