Identify base 2 for the following equation ac | vedclass

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(B) According to the $BRONSTED-LOWRY$ theory,an acid is a proton donor and a base is a proton acceptor.In the reaction: $HCl_{(aq)} + H_2O_{(l)} \righ

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$H_2O_{(l)}$

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(B) According to the $BRONSTED-LOWRY$ theory,an acid is a proton donor and a base is a proton acceptor.In the reaction: $HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(aq)}^{-}$$HCl$ acts as $Acid-1$ and donates a proton to $H_2O$,which acts as $Base-2$.After donating the proton,$HCl$ becomes $Cl^-$ $(Base-1)$ and $H_2O$ becomes $H_3O^+$ $(Acid-2)$.Therefore,$H_2O_{(l)}$ is the base $2$.

Identify base $2$ for the following equation according to the $BRONSTED-LOWRY$ theory.
$HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(aq)}^{-}$

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Identify base $2$ for the following equation according to the $BRONSTED-LOWRY$ theory.$HCl_{(aq)} + H_2O_{(l)} \rightleftharpoons H_3O_{(aq)}^{+} + Cl_{(aq)}^{-}$