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(B) The reaction of a carboxylic acid with soda lime $(NaOH + CaO)$ is known as decarboxylation.In this reaction,the $-COOH$ group is removed as $Na_2

Vedclass · Accepted Answer

$CH_3-CH(CH_3)-CH_3$

Vedclass · Answer

(B) The reaction of a carboxylic acid with soda lime $(NaOH + CaO)$ is known as decarboxylation.In this reaction,the $-COOH$ group is removed as $Na_2CO_3$ and replaced by a hydrogen atom.The reactant is $3$-methylbutanoic acid,$CH_3-CH(CH_3)-CH_2-COOH$.Upon heating with soda lime,the $-COOH$ group is eliminated,resulting in the formation of isobutane $(CH_3-CH(CH_3)-CH_3)$.

Identify the major product of the following reaction: $CH_3-CH(CH_3)-CH_2-COOH \xrightarrow{NaOH + CaO, \Delta}$

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