(D) Step $1$: $1,2-\text{Dibromoethane}$ $(BrCH_2-CH_2Br)$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form $A$,which is $Bromoethene$ $(CH_2

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(D) Step $1$: $1,2-\text{Dibromoethane}$ $(BrCH_2-CH_2Br)$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form $A$,which is $Bromoethene$ $(CH_2=CHBr)$.Step $2$: $Bromoethene$ $(CH_2=CHBr)$ reacts with $NaNH_2$ (sodamide),a strong base,to undergo further dehydrohalogenation to form $B$,which is $Ethyne$ $(HC \equiv CH)$.

Class 11 Chemistry Hydrocarbons Alkyne

Medium

Identify product $B$ in the following sequence of reactions.
$1,2-\text{Dibromoethane}$ $\xrightarrow[\text{alc. } KOH]{\Delta} A$ $\xrightarrow{NaNH_2} B$

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A
Bromoethane
B
Bromoethene
C
Ethene
D
Ethyne

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Identify product $B$ in the following sequence of reactions.$1,2-\text{Dibromoethane}$ $\xrightarrow[\text{alc. } KOH]{\Delta} A$ $\xrightarrow{NaNH_2} B$

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Identify product $B$ in the following sequence of reactions.
$1,2-\text{Dibromoethane}$ $\xrightarrow[\text{alc. } KOH]{\Delta} A$ $\xrightarrow{NaNH_2} B$

What is the major organic product of the following reaction?
$Ph-C \equiv CH \xrightarrow[H_2SO_4]{Hg^{2+}, H_2O} ?$