Difficult
Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.
- A$H_3C-C \equiv C-CH_3$
- B$H_3C-CH_2-C \equiv CH$
- C$H_2C=CH-C \equiv CH$
- D$HC \equiv C-CH_2-C \equiv CH$
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The gaseous mixture used for welding of metals is
The correct order of acidity of the following compounds is
$I. CH_3-C \equiv CH$ $II. F_3C-C \equiv CH$ $III. CH_3-C \equiv C-CH_3$ $IV. CH_3-CH=CH-CH_3$
| $I. CH_3-C \equiv CH$ |
| $II. F_3C-C \equiv CH$ |
| $III. CH_3-C \equiv C-CH_3$ |
| $IV. CH_3-CH=CH-CH_3$ |
Which of the following will be the final product when $C_2H_2$ reacts with $HCl$?
Medium
View SolutionWrite the following reaction:
$1$. Ozonolysis of ethyne.
$1$. Ozonolysis of ethyne.
Medium
View SolutionConsider the following sequence,where $A$ can be:
$A$ $(C_{3}H_{6}Cl_{2})$ $\xrightarrow[2. \, H^{+} \, (mild)]{1. \, \text{alcoholic } KOH / \Delta, \text{ followed by } NaNH_{2} / \Delta}$ $B$ $\xrightarrow[H_{2}O_{2} / OH^{-}]{B_{2}H_{6}}$ $C$
$A$ $\xrightarrow{aq. \, KOH \, (excess)}$ $C$
Identify $A$.
$A$ $(C_{3}H_{6}Cl_{2})$ $\xrightarrow[2. \, H^{+} \, (mild)]{1. \, \text{alcoholic } KOH / \Delta, \text{ followed by } NaNH_{2} / \Delta}$ $B$ $\xrightarrow[H_{2}O_{2} / OH^{-}]{B_{2}H_{6}}$ $C$
$A$ $\xrightarrow{aq. \, KOH \, (excess)}$ $C$
Identify $A$.
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