Identify the aromatic compound.

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) compound is aromatic if it follows $H$ückel's rule ($4n+2$ $\pi$ electrons),is planar,and cyclic.$A$: Cyclopentadienone has $4$ $\pi$ electrons in

Vedclass · Accepted Answer

$2-$aminopyridin$-4-$one

Vedclass · Answer

(C) compound is aromatic if it follows $H$ückel's rule ($4n+2$ $\pi$ electrons),is planar,and cyclic.$A$: Cyclopentadienone has $4$ $\pi$ electrons in the ring (anti-aromatic).$B$: Cycloheptatriene has an $sp^3$ hybridized carbon atom,so it is not planar and not aromatic.$C$: $2-$aminopyridin$-4-$one is a tautomer of $2-$amino$-4-$hydroxypyridine. The ring is planar,fully conjugated,and contains $6$ $\pi$ electrons ($4$ from double bonds + $2$ from the lone pair on the nitrogen atom in the ring),satisfying $H$ückel's rule $(n=1)$. Thus,it is aromatic.$D$: The structure shown is not aromatic due to the presence of $sp^3$ hybridized nitrogen and lack of continuous conjugation.

Similar Questions

The electrophile used in the sulfonation of benzene is..........

Which of the following compounds reacts slower than benzene in electrophilic bromination?

In benzene,the total number of $\sigma$ bonds is

Which of the following reactions is correct?

Explain why the following systems are not aromatic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module