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(A) The scheme shows that one component of the mixture reacts with both $NaOH(aq)$ and $NaHCO_3(aq)$ to become soluble,while the other remains insolub

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$(B, D)$

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(A) The scheme shows that one component of the mixture reacts with both $NaOH(aq)$ and $NaHCO_3(aq)$ to become soluble,while the other remains insoluble.$1.$ $C_6H_5COOH$ (benzoic acid) is a strong acid $(pK_a \approx 4.2)$ and reacts with both $NaOH$ and $NaHCO_3$ to form soluble sodium benzoate.$2.$ $C_6H_5CH_2COOH$ (phenylacetic acid) is also a strong acid and reacts with both $NaOH$ and $NaHCO_3$ to form soluble sodium phenylacetate.$3.$ $C_6H_5OH$ (phenol) is a weak acid $(pK_a \approx 10)$ and reacts with $NaOH$ to form soluble sodium phenoxide,but it does not react with $NaHCO_3$.$4.$ $C_6H_5CH_2OH$ (benzyl alcohol) is neutral and does not react with either $NaOH$ or $NaHCO_3$.Analyzing the options:- $(B)$ Mixture of $C_6H_5COOH$ (acid) and $C_6H_5CH_2OH$ (neutral): $C_6H_5COOH$ reacts with both $NaOH$ and $NaHCO_3$ (soluble),while $C_6H_5CH_2OH$ does not (insoluble). This fits the scheme.- $(D)$ Mixture of $C_6H_5CH_2COOH$ (acid) and $C_6H_5CH_2OH$ (neutral): $C_6H_5CH_2COOH$ reacts with both $NaOH$ and $NaHCO_3$ (soluble),while $C_6H_5CH_2OH$ does not (insoluble). This fits the scheme.Therefore,both $(B)$ and $(D)$ follow the given separation scheme.

Identify the binary mixture$(s)$ that can be separated into individual compounds by differential extraction,as shown in the given scheme.
$(A)$ $C_6H_5OH$ and $C_6H_5COOH$
$(B)$ $C_6H_5COOH$ and $C_6H_5CH_2OH$
$(C)$ $C_6H_5CH_2OH$ and $C_6H_5OH$
$(D)$ $C_6H_5CH_2OH$ and $C_6H_5CH_2COOH$

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Identify the binary mixture$(s)$ that can be separated into individual compounds by differential extraction,as shown in the given scheme.$(A)$ $C_6H_5OH$ and $C_6H_5COOH$$(B)$ $C_6H_5COOH$ and $C_6H_5CH_2OH$$(C)$ $C_6H_5CH_2OH$ and $C_6H_5OH$$(D)$ $C_6H_5CH_2OH$ and $C_6H_5CH_2COOH$