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(B) The boiling point of compounds depends on intermolecular forces such as hydrogen bonding and molar mass. $1$. Primary amines $(n-C_4H_9NH_2)$ and

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$C_2H_5CH(CH_3)_2$

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(B) The boiling point of compounds depends on intermolecular forces such as hydrogen bonding and molar mass. $1$. Primary amines $(n-C_4H_9NH_2)$ and secondary amines $((C_2H_5)_2NH)$ can form intermolecular hydrogen bonds,leading to higher boiling points. $2$. Tertiary amines $(C_2H_5N(CH_3)_2)$ cannot form intermolecular hydrogen bonds because they lack a hydrogen atom attached to the nitrogen. $3$. Alkanes $(C_2H_5CH(CH_3)_2)$ have only weak van der Waals forces. $4$. Comparing $C_2H_5N(CH_3)_2$ (molar mass $\approx 73 \ g/mol$) and $C_2H_5CH(CH_3)_2$ (molar mass $\approx 72 \ g/mol$),the tertiary amine has a higher boiling point due to the dipole-dipole interaction of the $C-N$ bond compared to the non-polar alkane. $5$. Therefore,$C_2H_5CH(CH_3)_2$ has the lowest boiling point.

Identify the compound from the following having the lowest boiling point.

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