Identify the compounds $A$ to $E$ in the following reaction sequence:
$(i)$ $CH_3CH_2OH \xrightarrow[dil. HCl]{KMnO_4/KOH} (A) + H_2O$
$(ii)$ $CH_3CH_2OH + A \xrightarrow[\Delta]{Conc. H_2SO_4} B + H_2O$
$(iii)$ $B + NaOH \rightarrow C + CH_3CH_2OH$
$(iv)$ $A + NaHCO_3 \rightarrow C + D + H_2O$
$(v)$ $CH_3CH_2OH + E \rightarrow CH_3CH_2ONa + H_2$

(A) $(i)$ Ethanol $(CH_3CH_2OH)$ undergoes oxidation with alkaline $KMnO_4$ to form Ethanoic acid $(A = CH_3COOH)$.
$(ii)$ Ethanol reacts with Ethanoic acid $(A)$ in the presence of concentrated $H_2SO_4$ to form Ethyl ethanoate $(B = CH_3COOCH_2CH_3)$ and water.
$(iii)$ Ethyl ethanoate $(B)$ undergoes saponification with $NaOH$ to form Sodium ethanoate $(C = CH_3COONa)$ and Ethanol.
$(iv)$ Ethanoic acid $(A)$ reacts with $NaHCO_3$ to form Sodium ethanoate $(C)$,Carbon dioxide $(D = CO_2)$,and water.
$(v)$ Ethanol reacts with Sodium $(E = Na)$ to form Sodium ethoxide $(CH_3CH_2ONa)$ and Hydrogen gas.