Identify the correct observation with respect | vedclass

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(B) For the first graph ($p$ vs $1/V$): According to the ideal gas equation $pV = nRT$, we have $p = (nRT) 	imes (1/V)$. The slope of the line is $nR

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$T_2 > T_1$ and $p_1 > p_2$

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(B) For the first graph ($p$ vs $1/V$): According to the ideal gas equation $pV = nRT$, we have $p = (nRT) 	imes (1/V)$. The slope of the line is $nRT$. Since the slope for $T_2$ is greater than the slope for $T_1$, it follows that $T_2 > T_1$.For the second graph ($V$ vs $T$): According to Charles' law $V = (nR/p) 	imes T$. The slope of the line is $nR/p$. Since the slope for $p_2$ is greater than the slope for $p_1$, and the slope is inversely proportional to pressure, it follows that $p_1 > p_2$.Therefore, the correct observation is $T_2 > T_1$ and $p_1 > p_2$.

Identify the correct observation with respect to the given graphs.

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