Identify the correct order of reactivity of t | vedclass

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(C) The reactivity of haloarenes towards nucleophilic substitution with $NaOH$ increases with the presence of electron-withdrawing groups (like $-NO_2

Vedclass · Accepted Answer

$II > IV > I > III$

Vedclass · Answer

(C) The reactivity of haloarenes towards nucleophilic substitution with $NaOH$ increases with the presence of electron-withdrawing groups (like $-NO_2$) on the benzene ring. These groups stabilize the carbanion intermediate formed during the reaction by withdrawing electron density through inductive and resonance effects.$1$. Compound $(II)$ has three $-NO_2$ groups (at ortho and para positions),providing maximum stabilization.$2$. Compound $(IV)$ has two $-NO_2$ groups (at ortho and para positions).$3$. Compound $(I)$ has one $-NO_2$ group at the para position.$4$. Compound $(III)$ has one $-NO_2$ group at the meta position,which provides the least stabilization compared to ortho/para positions because the negative charge is not delocalized onto the $-NO_2$ group via resonance.Thus,the order of reactivity is $(II) > (IV) > (I) > (III)$.Hence,option $(C)$ is correct.

Identify the correct order of reactivity of the following haloarenes on treatment with $NaOH$?

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