Identify the correct orders from the followin | vedclass

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(D) The order in '$A$' is correct because the bond angle decreases as the electronegativity of the central atom decreases down the group, leading to l

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$A, B$ & $D$ only

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(D) The order in '$A$' is correct because the bond angle decreases as the electronegativity of the central atom decreases down the group, leading to less repulsion between bond pairs.The order in '$B$' is correct because the electron density on the central atom decreases as the size of the atom increases, making the lone pair less available for donation.The order in '$C$' is incorrect because thermal stability decreases down the group due to the increase in bond length and decrease in bond dissociation energy. The correct order is $NH_3 > PH_3 > AsH_3 > SbH_3$.The order in '$D$' is correct. $NH_3$ has a high boiling point due to intermolecular $H$-bonding, while for the others $(PH_3, AsH_3, SbH_3)$, the boiling point increases down the group due to increasing van der Waals forces (molecular weight).Thus, the correct orders are $A, B$ and $D$.

Identify the correct orders from the following with respect to the property associated with:
$A$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Bond Angle
$B$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Basic Character
$C$. $PH_3 > AsH_3 > SbH_3 > NH_3$ - Thermal stability
$D$. $SbH_3 > NH_3 > AsH_3 > PH_3$ - Boiling point

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Identify the correct orders from the following with respect to the property associated with:$A$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Bond Angle$B$. $NH_3 > PH_3 > AsH_3 > SbH_3$ - Basic Character$C$. $PH_3 > AsH_3 > SbH_3 > NH_3$ - Thermal stability$D$. $SbH_3 > NH_3 > AsH_3 > PH_3$ - Boiling point