Identify the correct statement(s) from the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $(I)$ The catenation property of group $14$ elements decreases from carbon to tin. Carbon has a small atomic size, resulting in strong $C-C$ bonds

Vedclass · Accepted Answer

$I, III$

Vedclass · Answer

(B) $(I)$ The catenation property of group $14$ elements decreases from carbon to tin. Carbon has a small atomic size, resulting in strong $C-C$ bonds, which leads to maximum catenation. As we move down the group, atomic size increases, bond strength decreases, and the tendency for catenation decreases.$(II)$ Fullerene $(C_{60})$ consists of $20$ six-membered rings and $12$ five-membered rings. The statement in the question incorrectly swaps these values.$(III)$ $SiO_2$ is an acidic oxide and is soluble in strong alkaline solutions like $NaOH$ to form sodium silicate: $2NaOH + SiO_2 \longrightarrow Na_2SiO_3 + H_2O$.Therefore, statements $I$ and $III$ are correct.

Identify the correct statement$(s)$ from the following: $I$. The catenation property of group $14$ elements decreases from carbon to tin. $II$. Fullerene $(C_{60})$ has $20$ five-membered carbon rings and $12$ six-membered carbon rings. $III$. $SiO_2$ is soluble in conc. $NaOH$.

Similar Questions

Assertion : $Pb^{4+}$ compounds are stronger oxidizing agents than $Sn^{4+}$ compounds.
Reason : The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to 'inert pair effect'.

The stability of dihalides of $Si$,$Ge$,$Sn$ and $Pb$ increases steadily in the sequence

Which statement is wrong?

Silicon dissolves in excess of $HF$ due to the formation of:

$NaOCl$ is used as a bleaching agent and sterilising agent. It can be synthesized by the action of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module