Identify the correct statements from the foll | vedclass

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(D) $(I)$ The ionic radius of lanthanoids decreases with an increase in atomic number due to lanthanoid contraction. The order is $Pr^{3+} (1.013 \ \m

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$II, III$ only

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(D) $(I)$ The ionic radius of lanthanoids decreases with an increase in atomic number due to lanthanoid contraction. The order is $Pr^{3+} (1.013 \ \mathring{A}) > Sm^{3+} (0.964 \ \mathring{A}) > Dy^{3+} (0.908 \ \mathring{A})$. Thus,statement $(I)$ is incorrect.$(II)$ $Eu^{2+}$ $(Z = 63)$ has a stable $4f^7$ configuration but easily oxidizes to $Eu^{3+}$ $(4f^6)$,making it a strong reducing agent. Thus,statement $(II)$ is correct.$(III)$ $Pu$ $(Z = 94)$ has the electronic configuration $[Rn] 5f^6 6d^0 7s^2$. It can exhibit oxidation states up to $+7$ by utilizing its $5f, 6d,$ and $7s$ electrons. Thus,statement $(III)$ is correct.Therefore,the correct option is $(D)$.

Identify the correct statements from the following :
$I$. The ionic radius of $Pr^{3+}, Dy^{3+}$ and $Sm^{3+}$ follow the order,$Sm^{3+} > Pr^{3+} > Dy^{3+}$.
$II$. $Eu^{2+}$ acts as a strong reducing agent.
$III$. $Pu$ exhibits $+7$ oxidation state.

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Identify the correct statements from the following :$I$. The ionic radius of $Pr^{3+}, Dy^{3+}$ and $Sm^{3+}$ follow the order,$Sm^{3+} > Pr^{3+} > Dy^{3+}$.$II$. $Eu^{2+}$ acts as a strong reducing agent.$III$. $Pu$ exhibits $+7$ oxidation state.