Identify the correct trend of acidic strength | vedclass

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Question

(B) The acidic strength of alcohols depends on the stability of the conjugate base (alkoxide ion) formed after the release of a proton $(H^+)$. Alkyl

Vedclass · Accepted Answer

$(I) > (II) > (III)$

Vedclass · Answer

(B) The acidic strength of alcohols depends on the stability of the conjugate base (alkoxide ion) formed after the release of a proton $(H^+)$. Alkyl groups are electron-donating ($+I$ effect). As the number of alkyl groups attached to the carbon bearing the $-OH$ group increases,the electron density on the oxygen atom increases due to the $+I$ effect,which destabilizes the alkoxide ion. Therefore,the stability of the alkoxide ion follows the order: Primary $(1^{\circ})$ > Secondary $(2^{\circ})$ > Tertiary $(3^{\circ})$. Consequently,the acidic strength follows the same order: Primary $(I)$ > Secondary $(II)$ > Tertiary $(III)$. Thus,the correct order is $(I) > (II) > (III)$.

Identify the correct trend of acidic strength for the given alcohols.

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