Identify the logic gate represented by the gi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A \cdot B}$.This output is fed into a $NAND$ gate whose two inpu

Vedclass · Accepted Answer

$AND\, (A = 1, B = 1, Y = 1)$

Vedclass · Answer

(A) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A \cdot B}$.This output is fed into a $NAND$ gate whose two inputs are shorted together,which acts as a $NOT$ gate.Let the output of the first $NAND$ gate be $X = \overline{A \cdot B}$.The final output $Y$ is the inversion of $X$,so $Y = \overline{X} = \overline{(\overline{A \cdot B})} = A \cdot B$.Since the final output $Y = A \cdot B$,the circuit functions as an $AND$ gate.For $A = 1$ and $B = 1$,$Y = 1 \cdot 1 = 1$. Thus,option $A$ is correct.

Identify the logic gate represented by the given circuit and match the values of $A, B, Y$ in the bracket to verify.

Similar Questions

The circuit diagram shows a combination of logic gates. When inputs $P$ and $Q$ change to state $0$ with inputs $R$ and $S$ still at state $1$,the states of outputs $X$,$Y$ and $Z$ change to:

For the given logic circuit,to have the output $Y=1$,the possible combinations of inputs are:
$a) A=0, B=1$
$b) A=1, B=0$
$c) A=0, B=0$
$d) A=1, B=1$

$A$ truth table is given below. Which of the following logic gates corresponds to this truth table?
$A: 0, 1, 0, 1$
$B: 0, 0, 1, 1$
$Y: 1, 0, 0, 0$

The truth table for the given logic circuit is: (Inputs $A, B$ and Output $E$)

Give the truth table for the circuit shown in the figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module