Identify the incorrect match from the followi | vedclass

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(C) In $[Cr(H_2O)_6]Br_2$,$Cr$ is in $+2$ oxidation state $(3d^4)$,which has $4$ unpaired electrons,so it is paramagnetic.In $Na_4[Fe(CN)_6]$,$Fe$ is

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$[Ni(CO)_4]$ - Paramagnetic

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(C) In $[Cr(H_2O)_6]Br_2$,$Cr$ is in $+2$ oxidation state $(3d^4)$,which has $4$ unpaired electrons,so it is paramagnetic.In $Na_4[Fe(CN)_6]$,$Fe$ is in $+2$ oxidation state $(3d^6)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $0$ unpaired electrons,so it is diamagnetic.In $[Ni(CO)_4]$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of all electrons,resulting in $0$ unpaired electrons,so it is diamagnetic.In $Na_2[NiCl_4]$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $Cl^-$ is a weak field ligand,resulting in $2$ unpaired electrons,so it is paramagnetic.Therefore,the incorrect match is $[Ni(CO)_4]$ - Paramagnetic.

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