Identify the incorrect statement about the ox | vedclass

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Question

(C) In group $14$, the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. Therefore, $Pb^{2+}$ is the most s

Vedclass · Accepted Answer

Lead in $+2$ oxidation state is a reducing agent.

Vedclass · Answer

(C) In group $14$, the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. Therefore, $Pb^{2+}$ is the most stable state for lead. Consequently, $Pb^{2+}$ acts as an oxidizing agent because it tends to gain electrons to reach the more stable $Pb^0$ state or remain in the $Pb^{2+}$ state, whereas $Sn^{2+}$ acts as a reducing agent because it tends to lose electrons to reach the more stable $Sn^{4+}$ state. Thus, the statement that lead in $+2$ oxidation state is a reducing agent is incorrect.

Identify the incorrect statement about the oxidation states of group $14$ elements.

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