Identify the major product $(99 \%)$ formed when $(CH_3)_3CH$ is treated with $Br_2$ in $UV$ light.

  • A
    $(CH_3)_3CHCH_2Br$
  • B
    $(CH_3)_3CBr$
  • C
    $(CH_3)_2CHCH(CH_3)Br$
  • D
    $CH_3(CH_2)_2CH_2Br$

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