Identify the major product C in the given seq | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The reaction of acetone $(CH_3)_2C=O$ with $CH_3MgBr$ followed by acidic hydrolysis gives tert-butyl alcohol $(A)$,which is $(CH_3)_3C-OH$.$2

Vedclass · Accepted Answer

$CH_3-C(CH_3)=CH_2$

Vedclass · Answer

(A) $1$. The reaction of acetone $(CH_3)_2C=O$ with $CH_3MgBr$ followed by acidic hydrolysis gives tert-butyl alcohol $(A)$,which is $(CH_3)_3C-OH$.$2$. Treatment of $(A)$ with $SOCl_2$ leads to the formation of tert-butyl chloride $(B)$,which is $(CH_3)_3C-Cl$.$3$. The reaction of $(B)$ with $CH_3ONa$ (a strong base) under heating conditions leads to dehydrohalogenation via an $E2$ mechanism,resulting in the formation of isobutylene ($2$-methylpropene) as the major product $(C)$,which is $(CH_3)_2C=CH_2$.

Identify the major product $C$ in the given sequence of reactions.
$(CH_3)_2C=O$ $\xrightarrow[(ii) H^+/H_2O]{(i) CH_3MgBr/Ether} A$ $\xrightarrow[\Delta]{SOCl_2} B$ $\xrightarrow[\Delta]{CH_3ONa} C$

Similar Questions

Chloroform on reduction with zinc dust and water gives:

Which is the main organic product obtained by the reaction of $2,2,2-$trichloroethanol with calcium hydroxide?

The conversion of ethyl bromide to ethyl iodide using sodium iodide and dry acetone is known as:

When chloroform is treated with excess oxygen,it forms .....

What is the product formed when $Ethyl \ bromide$ reacts with alcoholic $Silver \ nitrite$ $(AgNO_2)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the major product $C$ in the given sequence of reactions.$(CH_3)_2C=O$ $\xrightarrow[(ii) H^+/H_2O]{(i) CH_3MgBr/Ether} A$ $\xrightarrow[\Delta]{SOCl_2} B$ $\xrightarrow[\Delta]{CH_3ONa} C$