Identify the major product formed when 2-Meth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dehydration of $2-$Methylhexan$-3-$ol with concentrated $H_2SO_4$ proceeds via an $E1$ mechanism involving the formation of a carbocation inte

Vedclass · Accepted Answer

$2-$Methylhex$-2-$ene

Vedclass · Answer

(A) The dehydration of $2-$Methylhexan$-3-$ol with concentrated $H_2SO_4$ proceeds via an $E1$ mechanism involving the formation of a carbocation intermediate.Upon protonation of the $-OH$ group and loss of water,a secondary carbocation is formed at the $C-3$ position.This carbocation can undergo a $1,2-$hydride shift to form a more stable tertiary carbocation at the $C-2$ position.According to the $Saytzeff$ rule,the major product is the most substituted alkene,which is formed by the elimination of a proton from the adjacent carbon to the tertiary carbocation.The resulting major product is $2-$Methylhex$-2-$ene.

Identify the major product formed when $2-$Methylhexan$-3-$ol is heated with concentrated sulphuric acid.

Similar Questions

Which of the following acts as both an oxidizing agent and a reducing agent?

If a point $(x, y) = (\tan \theta + \sin \theta, \tan \theta - \sin \theta)$,then the locus of $(x, y)$ is

Two wooden blocks of masses $M$ and $m$ are placed on a smooth horizontal surface as shown in the figure. If a force $P$ is applied to the system as shown in the figure such that the mass $m$ remains stationary with respect to the block of mass $M$, then the magnitude of the force $P$ is

Solid $BeH_2$ and solid $BeCl_2$ differ in

The point at which the circles $x^2+y^2-4x-4y+7=0$ and $x^2+y^2-12x-10y+45=0$ touch each other is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module