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(D) Kolbe's electrolysis of sodium propionate $(CH_3-CH_2-COONa)$ involves the decarboxylation of the carboxylate ion to form an alkyl radical.$2CH_3-

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$CH_3-CH_2-CH_2-CH_3$

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(D) Kolbe's electrolysis of sodium propionate $(CH_3-CH_2-COONa)$ involves the decarboxylation of the carboxylate ion to form an alkyl radical.$2CH_3-CH_2-COO^- \rightarrow 2CH_3-CH_2-COO^{\bullet} + 2e^-$$2CH_3-CH_2-COO^{\bullet} \rightarrow 2CH_3-CH_2^{\bullet} + 2CO_2$The ethyl radicals $(CH_3-CH_2^{\bullet})$ then dimerize to form butane $(CH_3-CH_2-CH_2-CH_3)$.$CH_3-CH_2^{\bullet} + CH_3-CH_2^{\bullet} \rightarrow CH_3-CH_2-CH_2-CH_3$

Identify the major product of the following reaction: $CH_3-CH_2-COONa \xrightarrow{\text{Kolbe's Electrolysis}}$

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