Identify the option in which the molecules are arranged in the correct order of their dipole moments.

  • A
    $CO_2 < H_2O < H_2S$
  • B
    $HF < HCl < HBr$
  • C
    $BF_3 < NF_3 < NH_3$
  • D
    $CH_4 < CHCl_3 < CCl_4$

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Similar Questions

Although both $CO_2$ and $H_2O$ are triatomic molecules,the shape of $H_2O$ molecule is bent while that of $CO_2$ is linear. Explain this on the basis of dipole moment.

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Given below are two statements:
Statement-$I$: Since fluorine is more electronegative than nitrogen,the net dipole moment of $NF_3$ is greater than $NH_3$.
Statement-$II$: In $NH_3$,the orbital dipole due to lone pair and the dipole moment of $N-H$ bonds are in opposite direction,but in $NF_3$ the orbital dipole due to lone pair and dipole moments of $N-F$ bonds are in same direction.
In the light of the above statements,choose the most appropriate from the options given below.

For which molecules among the following,the resultant dipole moment $(\mu) \neq 0?$

Which out of $NH_{3}$ and $NF_{3}$ has a higher dipole moment and why?

Which of the following compounds will show a dipole moment?

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