Identify the oxidation number of Sulphur in $SO_2$ and $SO_4^{2-}$ respectively.

  • A
    $+6, +4$
  • B
    $+4, +6$
  • C
    $+4, +3$
  • D
    $+3, +4$

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The oxidation state of elemental carbon is:

Consider the following molecules: $Br_3O_8$,$F_2O$,$H_2S_4O_6$,$H_2S_5O_6$,and $C_3O_2$. Count the number of atoms existing in their zero oxidation state in each molecule. Their sum is . . . . .

Assertion: In some cases,oxygen exhibits a positive oxidation state. Consequently,it is an electronegative element.
Reason: Fluorine is more electronegative than oxygen.

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One mole of $N_2H_4$ loses $10 \ moles$ of electrons to form a new compound $Z$. Assuming that all the nitrogen atoms appear in the new compound, what is the oxidation state of nitrogen in $Z$? (There is no change in the oxidation state of hydrogen.)

What are the oxidation numbers of $S$ atoms in $S_4O_6^{2-}$?

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