Identify the product X in the following react | vedclass

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(B) The reaction of sodium propanoate $(CH_3-CH_2-COONa)$ with soda-lime $(NaOH + CaO)$ is a decarboxylation reaction. During this process,the carboxy

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Ethane

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(B) The reaction of sodium propanoate $(CH_3-CH_2-COONa)$ with soda-lime $(NaOH + CaO)$ is a decarboxylation reaction. During this process,the carboxyl group is removed as $Na_2CO_3$,and the alkyl group forms an alkane with one carbon atom less than the original salt. $CH_3-CH_2-COONa + NaOH \xrightarrow{CaO, \Delta} CH_3-CH_3 + Na_2CO_3$. Thus,the product $X$ is ethane $(CH_3-CH_3)$.

Identify the product $X$ in the following reaction: $CH_3-CH_2-COONa \xrightarrow[\Delta]{\text{soda-lime}} X + Na_2CO_3$

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