Identify the product 'Y' in the following rea | vedclass

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(A) Step $1$: Reaction of $	ext{Benzonitrile}$ $(C_6H_5CN)$ with $	ext{Phenylmagnesium bromide}$ $(C_6H_5MgBr)$ leads to the formation of an imine i

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Benzophenone

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(A) Step $1$: Reaction of $	ext{Benzonitrile}$ $(C_6H_5CN)$ with $	ext{Phenylmagnesium bromide}$ $(C_6H_5MgBr)$ leads to the formation of an imine intermediate $(X)$, which is $	ext{N-magnesiobenzophenone imine}$ $(C_6H_5-C(=NMgBr)-C_6H_5)$.Step $2$: Acidic hydrolysis $(H_3O^+)$ of the intermediate $X$ converts the imine group into a carbonyl group, yielding $	ext{Benzophenone}$ $(C_6H_5-CO-C_6H_5)$ as the final product '$Y$', along with $MgBr(OH)$ and $NH_3$.

Identify the product '$Y$' in the following reaction: $\text{Benzonitrile} \xrightarrow{C_6H_5MgBr/\text{dry ether}} X \xrightarrow{H_3O^+} Y + MgBr(OH) + NH_3$

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