Identify the product obtained when benzonitri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) This reaction is known as the Stephen reduction. The reaction proceeds as follows:$1$. Benzonitrile $(C_6H_5-C \equiv N)$ is reduced by $SnCl_2$ a

Vedclass · Accepted Answer

Benzaldehyde

Vedclass · Answer

(D) This reaction is known as the Stephen reduction. The reaction proceeds as follows:$1$. Benzonitrile $(C_6H_5-C \equiv N)$ is reduced by $SnCl_2$ and $HCl$ to form an imine hydrochloride intermediate,benzanimine hydrochloride $(C_6H_5-CH=NH \cdot HCl)$.$2$. Subsequent acid hydrolysis $(H_3O^+)$ of the imine hydrochloride yields benzaldehyde $(C_6H_5-CHO)$ and ammonium chloride $(NH_4Cl)$.The overall reaction is: $C_6H_5-C \equiv N + 2[H]$ $\xrightarrow{SnCl_2, HCl} C_6H_5-CH=NH \cdot HCl$ $\xrightarrow{H_3O^+} C_6H_5-CHO + NH_4Cl$.

List-$I$ (Reagents)	List-$II$ (Reaction Name)
$A$. $H_2, Pd-BaSO_4$	$I$. Etard Reaction
$B$. $SnCl_2, HCl$	$II$. Rosenmund Reduction
$C$. $CrO_2Cl_2, CS_2$	$III$. Gatterman-Koch Reaction
$D$. $CO, HCl, \text{Anhyd. } AlCl_3$	$IV$. Stephen Reaction

Identify the product obtained when benzonitrile is reduced by stannous chloride $(SnCl_2)$ in the presence of hydrochloric acid $(HCl)$,followed by acid hydrolysis.

Similar Questions

Identify the reagent '$R$' used in the following reaction: $C_6H_5COCl \xrightarrow{R} C_6H_5CHO + HCl$

The reagents used in the Etard reaction $(I)$ and the Stephen reaction $(II)$ are:

Predict the product of the following reaction:
$m\text{-Tolunitrile} \xrightarrow[(ii) H_3O^+]{(i) CH_3MgBr} \text{Product}$

$CH_3COCH_3$ can be obtained by

Vedclass Test Series

Exam Paper Generator

Online Exam Module