Identify the products formed in the following | vedclass

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(C) The reaction of $2$-bromopentane $(CH_3-CH_2-CH_2-CHBr-CH_3)$ with alcoholic $KOH$ $(KOH / C_2H_5OH)$ is a dehydrohalogenation reaction (eliminati

Vedclass · Accepted Answer

$CH_3-CH_2-CH=CH-CH_3, CH_3-CH_2-CH_2-CH=CH_2$

Vedclass · Answer

(C) The reaction of $2$-bromopentane $(CH_3-CH_2-CH_2-CHBr-CH_3)$ with alcoholic $KOH$ $(KOH / C_2H_5OH)$ is a dehydrohalogenation reaction (elimination reaction). Alcoholic $KOH$ acts as a strong base and promotes the formation of alkenes via the $E2$ mechanism. According to Saytzeff's rule,the more substituted alkene is the major product. The possible elimination products are: $1$. Pent-$2$-ene $(CH_3-CH_2-CH=CH-CH_3)$ (Major product,more substituted) $2$. Pent-$1$-ene $(CH_3-CH_2-CH_2-CH=CH_2)$ (Minor product,less substituted) Therefore,the correct option is $C$.

Identify the products formed in the following reaction: $CH_3-CH_2-CH_2-CHBr-CH_3 \xrightarrow{KOH / C_2H_5OH} ?$

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