Identify the products formed when chlorine reacts with cold and dilute sodium hydroxide solution.

When $Br_2$ is treated with aqueous solutions of $NaF$,$NaCl$,and $NaI$ separately,what happens?

Find out which of the following statements are true or false:
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ is $(n-1)$.
$(b)$ When $F_2$ reacts with $H_2O$,it forms $HF$,$O_2$,and $O_3$.
$(c)$ $XeF_6$ on hydrolysis shows a disproportionation reaction.
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al(OH)_3$ as a final product.

What is the correct order of bond dissociation enthalpy for $N_2, O_2, F_2$ and $Cl_2$?

All the compounds listed in Column $I$ react with water. Match the result of the respective reactions with the appropriate options listed in Column $II$.

Column $I$	Column $II$
$(A). (CH_3)_2 SiCl_2$	$(p).$ Hydrogen halide formation
$(B). XeF_4$	$(q).$ Redox reaction
$(C). Cl_2$	$(r).$ Reacts with glass
$(D). VCl_5$	$(s).$ Polymerization
	$(t). O_2$ formation

Compound $A$ and $B$ respectively are :-
$Cl_2 + 2NaOH (cold \& dil.) \rightarrow A + NaCl + H_2O$
$3Cl_2 + 6NaOH (hot \& conc.) \rightarrow B + 5NaCl + 3H_2O$