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(A) The reaction between methanal $(HCHO)$ and benzaldehyde $(C_6H_5CHO)$ in the presence of concentrated $NaOH$ is a cross-Cannizzaro reaction.In thi

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Methanoic acid and phenyl methanol

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(A) The reaction between methanal $(HCHO)$ and benzaldehyde $(C_6H_5CHO)$ in the presence of concentrated $NaOH$ is a cross-Cannizzaro reaction.In this reaction,the more reactive aldehyde (methanal) undergoes oxidation to form a salt of carboxylic acid (sodium methanoate),which upon acidification $(H_3O^+)$ yields methanoic acid $(HCOOH)$.The less reactive aldehyde (benzaldehyde) undergoes reduction to form the corresponding alcohol,phenyl methanol $(C_6H_5CH_2OH)$.

$I. HNO_3$	$II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$	$IV. NaOH$

Identify the products of the following reaction:
$HCHO + C_6H_5CHO \xrightarrow[ii. \ H_3O^+]{i. \ conc. \ NaOH} ?$

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Identify the products of the following reaction:$HCHO + C_6H_5CHO \xrightarrow[ii. \ H_3O^+]{i. \ conc. \ NaOH} ?$