Identify the species X in the reaction: CH_3- | vedclass

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(D) The reaction of propene with concentrated acidic $KMnO_4$ is an oxidative cleavage reaction.$CH_3-CH=CH_2$ undergoes cleavage at the double bond.T

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Acetic acid

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(D) The reaction of propene with concentrated acidic $KMnO_4$ is an oxidative cleavage reaction.$CH_3-CH=CH_2$ undergoes cleavage at the double bond.The terminal $CH_2$ group is oxidized to $CO_2$ and $H_2O$,but under specific conditions or depending on the representation of the cleavage of the terminal carbon,it yields $HCOOH$ (formic acid).The $CH_3-CH=$ part is oxidized to acetic acid $(CH_3COOH)$.Therefore,the reaction is: $CH_3-CH=CH_2 + 4[O] \xrightarrow{KMnO_4/H^+} CH_3COOH + HCOOH$.

Identify the species $X$ in the reaction: $CH_3-CH=CH_2 + [O] \xrightarrow{\text{conc. acidic } KMnO_4} X + HCOOH$

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