Identify the structure of XeF_4 molecule from | vedclass

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(C) The central atom in $XeF_4$ is Xenon $(Xe)$,which has $8$ valence electrons.It forms $4$ single bonds with $4$ Fluorine $(F)$ atoms.This leaves $4

Vedclass · Accepted Answer

Square planar

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(C) The central atom in $XeF_4$ is Xenon $(Xe)$,which has $8$ valence electrons.It forms $4$ single bonds with $4$ Fluorine $(F)$ atoms.This leaves $4$ electrons,which form $2$ lone pairs on the Xenon atom.The total number of electron pairs around the central atom is $4$ (bond pairs) + $2$ (lone pairs) = $6$.According to $VSEPR$ theory,a steric number of $6$ corresponds to an octahedral electron geometry.With $4$ bond pairs and $2$ lone pairs,the lone pairs occupy the axial positions to minimize repulsion,resulting in a square planar molecular geometry.

Identify the structure of $XeF_4$ molecule from the following.

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