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(C) The reaction involves the reduction of a carboxylic acid using $LiAlH_4$ (Lithium aluminium hydride).$LiAlH_4$ is a strong reducing agent that red

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(C) The reaction involves the reduction of a carboxylic acid using $LiAlH_4$ (Lithium aluminium hydride).$LiAlH_4$ is a strong reducing agent that reduces carboxylic acids to primary alcohols.The reaction is:$C_6H_{11}COOH + 4[H] \xrightarrow{LiAlH_4} C_6H_{11}CH_2OH + H_2O$Here, the carboxylic acid group $(-COOH)$ is converted into a primary alcohol group $(-CH_2OH)$.Therefore, the product $A$ is cyclohexylmethanol, which corresponds to the structure shown in option $C$.

Identify the structure of product $A$ in the following reaction:
$\text{Cyclohexanecarboxylic acid} \xrightarrow{LiAlH_4} A$

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Identify the structure of product $A$ in the following reaction:$\text{Cyclohexanecarboxylic acid} \xrightarrow{LiAlH_4} A$