Identify the type of hybridization involved i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $NH_3$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which undergo $d^2sp^3$ hybridization to form an octahedral complex.

Column-$I$ Complex	Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$	$I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$	$II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$	$III$. Square planar / Diamagnetic

Identify the type of hybridization involved in the hexaamminecobalt$(III)$ complex ion.

Similar Questions

What is the color of the complex $[Co(H_2O)_6]Cl_3$?

Which of the following statements is correct?

Match the following:

Column-$I$ Complex Column-$II$ Structure / Geometry / Property

$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic

$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic

$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic

The correct match is:

Assertion $:$ Complex ion $[Co(NH_3)_6]^{2+}$ is readily oxidized to $[Co(NH_3)_6]^{3+}$.
Reason $:$ Unpaired electron in complex ion $[Co(NH_3)_6]^{2+}$ is present in $4p$ orbital.

Identify the number of unpaired electrons present and the geometry of the $[Co(NH_3)_6]^{3+}$ complex,respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module