Identify the values of A, B, C, D and E for t | vedclass

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(D) The given unbalanced reaction is: $aKNO_3 + 5C_{12}H_{22}O_{11} \rightarrow bN_2 + cCO_2 + dH_2O + eK_2CO_3$.To balance the equation, we equate th

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$A=48, B=24, C=36, D=55, E=24$

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(D) The given unbalanced reaction is: $aKNO_3 + 5C_{12}H_{22}O_{11} ightarrow bN_2 + cCO_2 + dH_2O + eK_2CO_3$.To balance the equation, we equate the number of atoms of each element on both sides:For $K$: $a = 2e$For $N$: $a = 2b$For $C$: $5 	imes 12 = c + e \Rightarrow 60 = c + e$For $H$: $5 	imes 22 = 2d$ $\Rightarrow 110 = 2d$ $\Rightarrow d = 55$For $O$: $3a + 5 	imes 11 = 2c + d + 3e$ $\Rightarrow 3a + 55 = 2c + 55 + 3e$ $\Rightarrow 3a = 2c + 3e$Setting $e = 24$, we get $a = 48$.Since $a = 2b$, $b = 24$.Since $c + e = 60$, $c = 60 - 24 = 36$.Thus, the balanced equation is: $48KNO_3 + 5C_{12}H_{22}O_{11} ightarrow 24N_2 + 36CO_2 + 55H_2O + 24K_2CO_3$.The values are $A=48, B=24, C=36, D=55, E=24$.

Identify the values of $A$, $B$, $C$, $D$ and $E$ for the following unbalanced reaction: $aKNO_3 + 5C_{12}H_{22}O_{11} \rightarrow bN_2 + cCO_2 + dH_2O + eK_2CO_3$

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