Identify what is Y in the following reaction | vedclass

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(C) The given reaction sequence is:$1$. $CH_3CONH_2 \xrightarrow{Br_2/NaOH(aq)} CH_3NH_2 (X)$This is the Hofmann bromamide degradation reaction,where

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$CH_3OH$

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(C) The given reaction sequence is:$1$. $CH_3CONH_2 \xrightarrow{Br_2/NaOH(aq)} CH_3NH_2 (X)$This is the Hofmann bromamide degradation reaction,where an amide is converted into a primary amine with one carbon atom less.$2$. $CH_3NH_2 (X) \xrightarrow[(ii) H_2O]{(i) NaNO_2 + HCl} CH_3OH (Y)$Primary aliphatic amines react with nitrous acid ($HNO_2$,generated in situ from $NaNO_2 + HCl$) to form unstable diazonium salts,which decompose in the presence of water to form alcohols.Therefore,$Y$ is methanol $(CH_3OH)$.

Column-$I$	Column-$II$
$A$. Benzenesulphonyl chloride	$1$. Zwitter ion
$B$. Sulphanilic acid	$2$. Hinsberg reagent
$C$. Alkyl diazonium salts	$3$. Dyes
$D$. Aryl diazonium salts	$4$. Conversion to alcohols

Identify what is $Y$ in the following reaction sequence?
$CH_3CONH_2$ $\xrightarrow{Br_2/NaOH(aq)} X$ $\xrightarrow[(ii) H_2O]{(i) NaNO_2 + HCl} Y$

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Column-$I$ Column-$II$

$A$. Benzenesulphonyl chloride $1$. Zwitter ion

$B$. Sulphanilic acid $2$. Hinsberg reagent

$C$. Alkyl diazonium salts $3$. Dyes

$D$. Aryl diazonium salts $4$. Conversion to alcohols

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(image)
The correct statement about $P$,$Q$,$R$,and $S$ is

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Identify what is $Y$ in the following reaction sequence?$CH_3CONH_2$ $\xrightarrow{Br_2/NaOH(aq)} X$ $\xrightarrow[(ii) H_2O]{(i) NaNO_2 + HCl} Y$