If $M_1$ and $M_2$ are the molecular weights of $Al(OH)_3$ and $H_3PO_3$ respectively,find their equivalent weights in the following reaction:
$Al(OH)_3 + 2H_3PO_3 \to Al(OH)(H_2PO_3)_2 + 2H_2O$
$Al(OH)_3 + 2H_3PO_3 \to Al(OH)(H_2PO_3)_2 + 2H_2O$
- A$\frac{M_1}{3}, \frac{M_2}{3}$
- B$\frac{M_1}{3}, \frac{M_2}{2}$
- C$\frac{M_1}{2}, \frac{M_2}{1}$
- D$\frac{M_1}{2}, \frac{M_2}{2}$
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