If $a, b, c$ are digits,then the rational number represented by $0.cababab...$ is:

  • A
    $\frac{9c+9b}{990}$
  • B
    $\frac{99c+10a+b}{99}$
  • C
    $\frac{99c+10a+b}{990}$
  • D
    None of these

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Let $p = 99$ and $q = 101$. Define $p_1 = \log_{10} \left(\frac{p+q}{2}\right)$ and $q_1 = \frac{1}{2}(\log_{10} p + \log_{10} q)$,and $p_2 = \log_{10} \left(\frac{p_1+q_1}{2}\right)$,$q_2 = \frac{1}{2}(\log_{10} p_1 + \log_{10} q_1)$. Then:

If $a^2 + 4b^2 = 12ab,$ then $\log(a + 2b)$ is

If ${a^x} = {(x + y + z)^y}$,${a^y} = {(x + y + z)^z}$,and ${a^z} = {(x + y + z)^x}$,then:

The rational form of the number $1.\overline{41}$ is

$0.5737373...... = $

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