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(A) Given: $w = [M]$,$x = [L]$,$y = [T]$,$z = [A]$.Substituting these dimensions into the expression $\frac{x^2w}{y^3z}$:$\left[\frac{x^2w}{y^3z}\righ

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electric potential

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(A) Given: $w = [M]$,$x = [L]$,$y = [T]$,$z = [A]$.Substituting these dimensions into the expression $\frac{x^2w}{y^3z}$:$\left[\frac{x^2w}{y^3z}\right] = \frac{[L]^2 [M]}{[T]^3 [A]} = \frac{[M][L]^2}{[T]^3 [A]}$.We know that electric potential $V = \frac{Work}{Charge} = \frac{[M][L]^2[T]^{-2}}{[A][T]} = \frac{[M][L]^2}{[T]^3 [A]}$.Comparing the two,the dimensional formula of $\frac{x^2w}{y^3z}$ is the same as that of electric potential.

If $w, x, y$ and $z$ are mass,length,time and current respectively,then $\frac{x^2w}{y^3z}$ has dimensional formula same as

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