If $\Delta_{0} < P$,then what is the electronic arrangement of the metal atom/ion in a complex with $d^4$ configuration?

The wavelengths of light absorbed by the complexes $[Ni(H_2O)_6]^{2+}$,$[Ni(en)_3]^{2+}$,and $[Ni(H_2O)_4en]^{2+}$ are $\lambda_1$,$\lambda_2$,and $\lambda_3$ respectively. The correct order of wavelengths is:

Which relationship is correct for the crystal field splitting energy between octahedral $(\Delta_0)$ and tetrahedral $(\Delta_t)$ complexes?

The correct order of the complexes $[Co(NH_3)_5(H_2O)]^{3+}$ $(A)$,$[Co(NH_3)_6]^{3+}$ $(B)$,$[Co(CN)_6]^{3-}$ $(C)$,and $[CoCl(NH_3)_5]^{2+}$ $(D)$ in terms of the wavelength of light absorbed is:

Arrange the following in increasing order of their crystal field splitting energy:
$I. [Co(H_2O)_6]^{3+}$
$II. [Co(NH_3)_6]^{3+}$
$III. [Co(CN)_6]^{3-}$
$IV. [CoF_6]^{3-}$

Select the correct order of $\Delta_o$ (Crystal Field Splitting Energy).