If P to T are second period p-block elements, | vedclass

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(A) The second period $p-$block elements are $B, C, N, O, F$. Let $P=B, Q=C, R=N, S=O, T=F$. The corresponding diatomic molecules are $B_2, C_2, N_2,

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(A) The second period $p-$block elements are $B, C, N, O, F$. Let $P=B, Q=C, R=N, S=O, T=F$. The corresponding diatomic molecules are $B_2, C_2, N_2, O_2, F_2$.       Species    Valence Electrons    Bond Order        $B_2$ $(P_2)$    $6$    $1.0$        $C_2$ $(Q_2)$    $8$    $2.0$        $N_2$ $(R_2)$    $10$    $3.0$        $O_2$ $(S_2)$    $12$    $2.0$        $F_2$ $(T_2)$    $14$    $1.0$  As the number of valence electrons increases from $6$ to $10$,the bond order increases from $1.0$ to $3.0$. As the number of valence electrons increases further from $10$ to $14$,the bond order decreases from $3.0$ to $1.0$. This trend is represented by the graph in option $A$.

If $P$ to $T$ are second period $p-$block elements,then which of the following graphs shows the correct relation between the number of valence electrons in $P_2$ to $T_2$ (corresponding molecules) and their bond order?

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