If CO ligands are substituted by NO in respec | vedclass

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(D) The $CO$ ligand is a $2e^-$ donor,while the $NO$ ligand acts as a $3e^-$ donor in neutral metal carbonyls.To maintain the $18e^-$ rule,the total n

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$Ni(CO)_2(NO)_2$

Vedclass · Answer

(D) The $CO$ ligand is a $2e^-$ donor,while the $NO$ ligand acts as a $3e^-$ donor in neutral metal carbonyls.To maintain the $18e^-$ rule,the total number of electrons must remain constant.Substituting $CO$ with $NO$ requires that the total electron count remains unchanged.For $Cr(CO)_6$ $(18e^-)$,replacing three $CO$ $(3 	imes 2e^- = 6e^-)$ with two $NO$ $(2 	imes 3e^- = 6e^-)$ gives $Cr(CO)_3(NO)_2$,which is valid.For $Fe(CO)_5$ $(18e^-)$,replacing three $CO$ with two $NO$ gives $Fe(CO)_2(NO)_2$,which is valid.For $Ni(CO)_4$ $(18e^-)$,replacing two $CO$ with one $NO$ would give $Ni(CO)_2(NO)$,but $Ni(CO)_2(NO)_2$ would result in $20e^-$,which is incorrect.Thus,$Ni(CO)_2(NO)_2$ is not a stable neutral complex following the $18e^-$ rule.

If $CO$ ligands are substituted by $NO$ in respective neutral carbonyl compounds,then which of the following will not be a correct formula?

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