If $x$ is the specific conductance (in $S \ cm^{-1}$) of an electrolyte solution and $y$ is the molarity of the solution,then $\Lambda_m$ (in $S \ cm^2 \ mol^{-1}$) is given by:

The molar conductivities of $KCl$,$NaCl$,and $KNO_3$ are $152$,$128$,and $111 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of $NaNO_3$ is ............. $S \ cm^2 \ mol^{-1}$.

$\Lambda _m^\circ$ for $NaCl$,$HCl$ and $NaAc$ are $126.4$,$425.9$ and $91.0 \ S \ cm^2 \ mol^{-1}$ respectively. Calculate $\Lambda _m^\circ$ for $HAc$.

The resistance of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $1500 \ \Omega$. If the conductivity of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $0.1466 \times 10^{-3} \ S \ cm^{-1}$,the cell constant of the conductivity cell in $cm^{-1}$ is:

Which solution of $NaCl$ will show the highest resistance during the passage of current (in $N$)?

The following figure shows the dependence of molar conductance of two electrolytes on concentration. $\Lambda_m^0$ is the limiting molar conductivity. The number of incorrect statement$(s)$ from the following is $...........$
$(A)$ $\Lambda_m^0$ for electrolyte $A$ is obtained by extrapolation.
$(B)$ For electrolyte $B$,the $\Lambda_m$ vs $\sqrt{c}$ graph is a straight line with an intercept equal to $\Lambda_m^0$.
$(C)$ At infinite dilution,the value of the degree of dissociation approaches zero for electrolyte $B$.
$(D)$ $\Lambda_m^0$ for any electrolyte $A$ or $B$ can be calculated using $\lambda^0$ for individual ions.