If A = {x in R : |x|

Question

(C) Given $A = \{x \in R : |x| < 2\} = (-2, 2)$.Given $B = \{x \in R : |x - 2| \geq 3\}$.This implies $x - 2 \geq 3$ or $x - 2 \leq -3$.So,$x \geq 5$

Vedclass · Accepted Answer

$B - A = R - (-2, 5)$

Vedclass · Answer

(C) Given $A = \{x \in R : |x| Given $B = \{x \in R : |x - 2| \geq 3\}$.This implies $x - 2 \geq 3$ or $x - 2 \leq -3$.So,$x \geq 5$ or $x \leq -1$.Thus,$B = (-\infty, -1] \cup [5, \infty)$.Now,$B - A$ is the set of elements in $B$ that are not in $A$.$B - A = ((-\infty, -1] \cup [5, \infty)) - (-2, 2)$.Since $(-2, 2)$ overlaps with $(-\infty, -1]$ only on the interval $(-2, -1]$,we remove this part.$B - A = (-\infty, -2] \cup [5, \infty)$.This can be written as $R - (-2, 5)$.Therefore,the correct option is $C$.

If $A = \{x \in R : |x| < 2\}$ and $B = \{x \in R : |x - 2| \geq 3\}$,then:

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