If $p \rightarrow (p \wedge \neg q)$ is false,then the truth values of $p$ and $q$ are respectively

Given the following two statements:
$(S_{1}): (q \vee p) \rightarrow (p \leftrightarrow \sim q)$ is a tautology.
$(S_{2}): \sim q \wedge (\sim p \leftrightarrow q)$ is a fallacy.
Then:

The converse of $[p \wedge (\sim q)] \rightarrow r$ is

The statement $(p \wedge q) \Rightarrow (p \wedge r)$ is equivalent to:

The logical expression $[p \wedge (q \vee r)] \vee [(\sim p \wedge q) \vee (\sim p \wedge r)]$ is equivalent to

Write the following statement in the form "if-then":
$A$ quadrilateral is a parallelogram if its diagonals bisect each other.